When vapours of ethyl alcohol are passed over `Al_(2)O_(3)` at `250^(@)C`, it forms

Options

A. Ethyl alcohol
B. Ethane
C. Diethyl ether
D. Glycol

Explanation

To solve the question, we need to understand the reaction that occurs when vapors of ethyl alcohol (ethanol) are passed over aluminum oxide (Al₂O₃) at a temperature of 250°C. This process involves dehydration, which leads to the formation of ether.

### Step-by-Step Solution:

1. **Identify the Reactants**:
- The reactant in this case is ethyl alcohol (ethanol), which has the chemical formula C₂H₅OH.

2. **Understand the Reaction Conditions**:
- The reaction takes place over aluminum oxide (Al₂O₃) at a temperature of 250°C. Aluminum oxide acts as a catalyst in this dehydration reaction.

3. **Dehydration Process**:
- When two molecules of ethyl alcohol are subjected to dehydration, they lose a water molecule (H₂O) and form an ether. The general reaction can be represented as:
\[ 2 \, \text{C}_2\text{H}_5\text{OH} \xrightarrow{\text{Al}_2\text{O}_3, 250^\circ C} \text{C}_2\text{H}_5\text{O}\text{C}_2\text{H}_5 + \text{H}_2\text{O} \]
- Here, diethyl ether (C₂H₅OC₂H₅) is formed along with water.

4. **Identify the Product**:
- The product formed from this reaction is diethyl ether, which is represented by the formula C₂H₅OC₂H₅.

5. **Conclusion**:
- Therefore, when vapors of ethyl alcohol are passed over Al₂O₃ at 250°C, the main product formed is diethyl ether.

### Final Answer:
The product formed is **diethyl ether**.