Glucose on treatment with `NH_2 OH` undergoes

Options

A. condensation
B. reduction
C. hydrolysis
D. oxidation

Explanation

To solve the question regarding the reaction of glucose with hydroxylamine (NH2OH), we will break down the process step by step.

### Step-by-Step Solution:

1. **Identify the Reactants**:
- The reactants in this reaction are glucose (a monosaccharide) and hydroxylamine (NH2OH).

2. **Understand the Functional Groups**:
- Glucose contains an aldehyde functional group (as it is an aldose sugar). Hydroxylamine is a reagent that reacts specifically with carbonyl groups (aldehydes and ketones).

3. **Reaction Mechanism**:
- When glucose is treated with hydroxylamine, the aldehyde group of glucose reacts with hydroxylamine. This reaction is a condensation reaction where water is eliminated.

4. **Formation of Oxime**:
- The product of this reaction is an oxime. In this case, the reaction of glucose with hydroxylamine leads to the formation of glucosamine oxime (also known as glucosyl oxime). The general structure of the oxime is characterized by the -C=N-OH functional group.

5. **Significance of the Reaction**:
- This reaction is significant as it serves as a test for the presence of the carbonyl group in glucose. The formation of the oxime indicates that glucose contains a carbonyl group.

6. **Conclusion**:
- Therefore, the final product of the reaction of glucose with hydroxylamine is glucosamine oxime, confirming the presence of the carbonyl group in glucose.

### Final Answer:
Glucose on treatment with hydroxylamine (NH2OH) undergoes a condensation reaction to form glucosamine oxime, indicating the presence of a carbonyl group in glucose.

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