Differentiate the following w.r.t x
`sin^(-1)(2x//1+x^(2))`

Explanation

To differentiate the function \( y = \sin^{-1}\left(\frac{2x}{1+x^2}\right) \) with respect to \( x \), we will follow these steps:

### Step 1: Identify the function and its derivative
We know that the derivative of \( \sin^{-1}(u) \) with respect to \( x \) is given by:
\[ \frac{d}{dx} \sin^{-1}(u) = \frac{1}{\sqrt{1 - u^2}} \cdot \frac{du}{dx} \]
where \( u = \frac{2x}{1+x^2} \).
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