Differentiate w.r.t x
`sqrt(x) (2x+3)^(2)//sqrt(x+1)`

Explanation

To differentiate the function \( y = \frac{\sqrt{x} (2x + 3)^2}{\sqrt{x + 1}} \) with respect to \( x \), we will use the quotient rule and the product rule. Let's go through the steps systematically.

### Step 1: Rewrite the Function
We can rewrite the function to make differentiation easier:
\[ y = \frac{(2x + 3)^2}{\sqrt{x + 1}} \cdot \sqrt{x} \]
This allows us to see it as a product of two functions: \( A = (2x + 3)^2 \) and \( B = \sqrt{x + 1} \).
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