Write down the expression for the elastic potential energy of a stretched wire.

Energy of a stretched wire is

The elastic potential energy of a stretched wire is given by

Write down the expression for the stationary wave.

Elastic potential energy is due to stretching or bending.

State Hooke's law. A metallic wire of Young's modulus Y is stretched by suspending a load from it. If the linear strain produced in it is mu , obtain an expression for the elastic potential energy, in terms of Y and mu , stored in unit volume of the wire.

A steel wire of 4.0 m is stretched through 2.0 mm. The cross - sectional area of the wire is 2.0 mm^2. If young's modulus of steel is 2.0 xx10^(11) Nm^(-2) find (i) the energy density of the wire, (ii) the elastic potential energy stored in the wire.

A steel wire 4.0m in length is stretched through 2.0mm .The cross -sectional area of the wire is 2.0 mm^(2) .If young's modulus of steel is 2.0xx10^(11) N//m^(2) (a) the energy density of wire, (b) the elastic potential energy stored in the wire.

A uniform wire of length L and radius r is twist by an angle alpha . If modulus of rigidity of the wire is eta , then the elastic potential energy stored in wire

Write an expression for the potential energy of a body of mass m placed at a height h above the earth's surface. State the assumptions made, if any

A wire 2 m in length suspended vertically stretches by. 10 mm when mass of 10 kg is attached to the lower end. The elastic potential energy gain by the wire is (take g = 10 m//s^(2) )