Calculate the frequency of revolution of a hydrogen molecule at `27^(@)C` about it own axis, assuming it to be diatomic with distance between the atoms as `1.5 Å`. Mass of each atom is `1.67 xx 10^(-27)kg. k = 1.38 xx 10^(-23) JK^(-1)`

Answer

`3.34 xx 10^(12) Hz`

Explanation

A diatomic molecule has two degress of freedom `( 1//2) I omega^(2) = 2 xx 10^(12) Hz`
Frequency `n = omega //2 pi = ( 1//2 pi ) sqrt( 2k T//I ) = ( 1// 2 sqrt) sqrt( 4kT// m r^(2)) = 3.34 xx 10^(12) Hz`