The root mean square speed of smoke particles each of mass `5xx10^(-17)` kg in their Brownian motion in air at N.T.P is

Answer

`1.5 XX 10^(-2) ms^(-1)`

Explanation

`( 1//2) mv_(rms) ^(2) = ( 3//2) kT, v_(rms) = sqrt( 3kT//m) = sqrt( 3 xx 1.38 xx 10^(-23) xx 273 // 10^(-17)) = 1.5 xx 10^(-2) ms^(-1)`