Two bodies of masses `m_(1)` and `m_2 (m_1 gt m_2)` respectively are tied to the ends j of a string which passes over a light frictionless pulley. The masses are intitially at rest and released. What is the acceleration of the centre of mass ?

Options

A. `((m_(1)-m_(2))/(m_(1) + m_(2)))^(2)`
B. `((m_(1)-m_(2))/(m_(1) + m_(2)))` g
C. g
D. zero

Answer

A

Explanation

`(m_(1) + m_(2)) veca_(c ) = m_(1)a_(1) + m_(2)veca_(2) = m_(1)veca - m_(2)veca`
`veca = [(m_(1)-m_(2))//(m_(1) + m_(2))]g`,
`a_(c ) = (m_(1)-m_(2))^(2) g//(m_(1) + m_(2))`