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The normal density of gold is rho and i...

The normal density of gold is `rho` and its bulk modulus is K. The increase is density of a lump of gold when a pressure P is applied uniformly on all sides is

A

`rho` P/K

B

`rho` K/P

C

`P//rho` K

D

`K//rho P`

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The correct Answer is:
To solve the problem of finding the increase in density of a lump of gold when a pressure \( P \) is applied uniformly on all sides, we can follow these steps: ### Step-by-Step Solution: 1. **Understand the Relationship Between Density and Volume**: Density (\( \rho \)) is defined as mass (\( m \)) divided by volume (\( V \)): \[ \rho = \frac{m}{V} \] When pressure is applied, the volume of the gold will change, but the mass will remain constant. 2. **Define the Change in Volume**: Let \( \Delta V \) be the change in volume due to the applied pressure. The new volume \( V' \) can be expressed as: \[ V' = V - \Delta V \] 3. **Express the New Density**: The new density \( \rho' \) after the change in volume can be expressed as: \[ \rho' = \frac{m}{V - \Delta V} \] 4. **Relate the Change in Density to the Original Density**: The change in density \( \Delta \rho \) can be defined as: \[ \Delta \rho = \rho' - \rho \] Substituting the expression for \( \rho' \): \[ \Delta \rho = \frac{m}{V - \Delta V} - \frac{m}{V} \] 5. **Use Bulk Modulus Definition**: The bulk modulus \( K \) is defined as: \[ K = -\frac{P}{\frac{\Delta V}{V}} \] Rearranging gives: \[ \frac{\Delta V}{V} = -\frac{P}{K} \] 6. **Relate Change in Volume to Change in Density**: From the definition of density, we can relate the change in volume to the change in density: \[ \Delta \rho = \rho \cdot \left(-\frac{\Delta V}{V}\right) \] Substituting for \( \frac{\Delta V}{V} \): \[ \Delta \rho = \rho \cdot \left(\frac{P}{K}\right) \] 7. **Final Expression for Increase in Density**: Thus, the increase in density \( \Delta \rho \) can be expressed as: \[ \Delta \rho = \frac{P \cdot \rho}{K} \] ### Conclusion: The increase in density of the lump of gold when a pressure \( P \) is applied uniformly on all sides is given by: \[ \Delta \rho = \frac{P \cdot \rho}{K} \]

To solve the problem of finding the increase in density of a lump of gold when a pressure \( P \) is applied uniformly on all sides, we can follow these steps: ### Step-by-Step Solution: 1. **Understand the Relationship Between Density and Volume**: Density (\( \rho \)) is defined as mass (\( m \)) divided by volume (\( V \)): \[ \rho = \frac{m}{V} ...
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