Let `Y_(g) and Y_(r )` represent Young's modulus for glass and rubber respectively. It is said that glass is more elastic than rubber. Therefore , it follows

Options

A. `Y_(g) = Y_(r )`
B. `Y_(g) lt Y_(r )`
C. `Y_(g) gt Y_(r )`
D. `Y_(g)//Y_(r ) = 0`

Explanation

To solve the problem, we need to understand the relationship between Young's modulus and the elasticity of materials. The question states that glass is more elastic than rubber, and we need to express this in terms of Young's modulus.

### Step-by-Step Solution:

1. **Understanding Young's Modulus**:
Young's modulus (Y) is defined as the ratio of stress (force per unit area) to strain (deformation in length/original length). It is a measure of the stiffness of a material.

\[ Y = \frac{\text{Stress}}{\text{Strain}} \]

2. **Comparing Young's Modulus of Glass and Rubber**:
We denote the Young's modulus for glass as \( Y_g \) and for rubber as \( Y_r \). The statement "glass is more elastic than rubber" implies that glass can deform less under the same amount of stress compared to rubber.

3. **Interpreting Elasticity**:
If a material is more elastic, it means it has a higher Young's modulus. Therefore, we can express this relationship mathematically as:

\[ Y_g > Y_r \]

4. **Conclusion**:
Since it is given that glass is more elastic than rubber, we conclude that the Young's modulus of glass is greater than that of rubber.

\[ \text{Thus, } Y_g > Y_r \]

### Final Answer:
The Young's modulus of glass is greater than the Young's modulus of rubber, i.e., \( Y_g > Y_r \).

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