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An observer saw a flash of lightning and...

An observer saw a flash of lightning and after 8 seconds heard the thunder. If the average temperature of air is `17^@C`, how far away did the lightning occur ? Velocity of sound in air at `0^@C" is 331 ms"^(-1)`.

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To find out how far away the lightning occurred, we can follow these steps: ### Step 1: Calculate the speed of sound at 17°C The formula to calculate the speed of sound at a temperature \( T \) in Celsius is given by: \[ V = V_0 \times \sqrt{\frac{T + 273}{273}} \] where: - \( V_0 \) is the speed of sound at 0°C (331 m/s), - \( T \) is the temperature in Celsius (17°C). First, we convert 17°C to Kelvin: \[ T = 17 + 273 = 290 \text{ K} \] Now, substituting the values into the formula: \[ V = 331 \times \sqrt{\frac{290}{273}} \] Calculating the square root: \[ \sqrt{\frac{290}{273}} \approx 1.030 \] Now, substituting this back into the equation for \( V \): \[ V \approx 331 \times 1.030 \approx 341.15 \text{ m/s} \] ### Step 2: Calculate the distance to the lightning The distance \( D \) can be calculated using the formula: \[ D = V \times t \] where: - \( V \) is the speed of sound we just calculated (341.15 m/s), - \( t \) is the time taken for the sound to travel (8 seconds). Substituting the values: \[ D = 341.15 \times 8 \] Calculating the distance: \[ D \approx 2729.2 \text{ meters} \] ### Conclusion The lightning occurred approximately 2729.2 meters away from the observer. ---
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