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A string of mass 2.5 kg is under tenstio...

A string of mass 2.5 kg is under tenstion of 200N . The length of the stretched string is 20.0 . If the transverse jerk is struck at one end of the string, the disturbance will reach the other end in

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The correct Answer is:
`mu=2.5//20 kgm^(-1), v=sqrt(7mu)=sqrt(200 xx 20//25)=40ms^(-1)`, Time =20/40=0.5 second
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