Find whether (4,-2) is on the exterior, interior or on the circle whose centre is (-3,1) and radius `sqrt5`.

Explanation

Equation the circle is `(x+3)^2+(y-1)^2=(sqrt5)^2`
or, `(4+3)^2+(-2-1)^2=(sqrt5)^2 =49+9-5=53 gt 0`
`therefore` the point (4,- 2) is exterior to the circle.