The foci of a hyperbola coincide with the foci of the ellipse `x^2/25 +y^2/9 =1`. Find the equation of the hyperbola if its eccentricity is 2.

Find the equation of a hyperbola, having foci (+- 7. 0) and its eccentricity is 4//3 .

If the foci of (x^2)/(a^2)-(y^2)/(b^2)=1 coincide with the foci of (x^2)/(25)+(y^2)/9=1 and the eccentricity of the hyperbola is 2, then

Find the foci of the ellipse 25(x+1)^2+9(y+2)^2=225.

The foci of the hyperbola 4x^2-9y^2=36 is

The foci of the ellipse x^2/25+y^2/9=1 coincide with a hyperbola. If e=2 for hyperbola, find the equation of hyperbola.

The distance between the foci of a hyperbola is 16 and its eccentricity is sqrt(2) then equation of the hyperbola is

let the eccentricity of the hyperbola x^2/a^2-y^2/b^2=1 be reciprocal to that of the ellipse x^2+4y^2=4. if the hyperbola passes through a focus of the ellipse then: (a) the equation of the hyperbola is x^2/3-y^2/2=1 (b) a focus of the hyperbola is (2,0) (c) the eccentricity of the hyperbola is sqrt(5/3) (d) the equation of the hyperbola is x^2-3y^2=3

Find the equation of the hyperbola whose foci are (8,3)a n d(0,3) and eccentricity is 4/3dot

Find the equation of hyperbola : Whose foci are (4, 2) and (8, 2) and eccentricity is 2.

The coordinates of the foci of a hyperbola are (16,0) and (-8,0) and its eccentricity is 3, find the equation of the hyperbola and the length of its latus rectum.