P(A-B)=1/3,P(A)=1/2,P(B)=1/3 calculate the probability that out of the two events A and B only B will occur

If P(A - B) = 1/3, P(A) =1/2 and P(B)= 1/3 , calculate the probability that out of the two events A and B, only B will occur.

If P(A-B) = (1)/(3) , P(A) = (1)/(2) and P(B) = (1)/(3), calculate the probability that our of the two events A and B , only B will occur.

If P(A - B) = 1/3,P(A) =1/2 and P(B) =1/3 ,find the probability that out of the events A and B. Only the event B occurs.

if P(A|B) = 1/3 , P(A) = 1/4 and P(B) = 1/2, find the probability that exactly one of the events A and B occurs.

If P(A//B)=(1)/(3), P(B)=(1)/(4) and P(A)=(1)/(2) , find the probability that exactly one of the events A and B occurs.

If P(A) = 2/7, P(B) = 6/11, what is the probability that at least one of the two independent events A and B will occur?

Show that the probability that exaclty one of the events A and B occurs is P(A) + P(B) - 2P(AB).

Show that the probability that exactly one of the events A and B occurs is P(A) + P(B) - 2P(AB).

If P(A)=(2)/(3),P(B)=(1)/(2) and P(A cap B)=(1)/(6) State wheather the events A and B are

For the three events A ,B , and C , P (exactly one of the events A or B occurs)= P (exactly one of the two evens B or C )= P (exactly one of the events C or A occurs)= p and P (all the three events occur simultaneously)= p^2 where 0 < p < 1//2 . Then the probability of at least one of the three events A , B and C occurring is