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underset(x to 1)"Lt"(1-x^(1/3))/(1-x^(2/...

`underset(x to 1)"Lt"(1-x^(1/3))/(1-x^(2/3))`

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`underset(x to 1)"Lt"(1-x^(1/3))/(1-x^(2/3)) = lim_(x to 1) (1-x^(1/3))/((1-x^(1/3))(1+x^(1/3))`
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