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Consider the circle x^2 + y^2 - 10x - 6y...

Consider the circle `x^2 + y^2 - 10x - 6y + 30 = 0` Let O be the centre of the circle and tangent at A(7, 3) and passing through A and B,then

A

area of quadrilateral OACB = 4

B

the radical axis for the family of circles S = O is x + y = 10

C

the smallest possible circle of the family S = 0 is `x^2 + y^2 - 12x - 4y + 38 = 0`

D

the coordinates of point C are (7, 1)

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A, C, D
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