The circle x^2 + y^2 - 4x - 8y + 16 = 0 ...

The circle `x^2 + y^2 - 4x - 8y + 16 = 0` rolls up along the tangent to it at `(2 + sqrt3, 3)` by 2 units. Assuming the x-axis as horizontal, find the equation of the circle in the new position.

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