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A circle of constant radius 'r' passes t...

A circle of constant radius 'r' passes through origin O and cuts the axes of coordinates in points P and Q, then the equation of the locus of the foot of perpendicular from O to PQ is

A

`(x^2+y^2) (x^-2+y^-2)=4r^2`

B

`(x^2+y^2)^2 (x^-2+y^-2)=r^2`

C

`(x^2+y^2)^2 (x^-2+y^-2)=4r^2`

D

`(x^2+y^2)(x^-2+y^-2)=r^2`

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