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If one end of a diameter of the circle x...

If one end of a diameter of the circle `x^2+y^2-4x-6y+11=0` is (3, 4) then the other end is

A

(2, 1)

B

(2, 4)

C

(1, 2)

D

(-4, 2)

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The correct Answer is:
C
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PATHFINDER-CIRCLE-QUESTION BANK
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