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A tangent PT is drawn to the circle x^2+...

A tangent PT is drawn to the circle `x^2+y^2 =4` at the point `P(sqrt3,1)`. A straight line L, perpendicular to PT is a tangent to the circle.
`(x - 3)^2+ y^2 = 1`
A possible equation of L is

A

`x-sqrt3y=1`

B

`x+sqrt3y=1`

C

`x-sqrt3y=-1`

D

`x-sqrt3y=5`

Text Solution

Verified by Experts

The correct Answer is:
A
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