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If the circles x^2 + y^2 + 2x + 2ky + 6 ...

If the circles `x^2 + y^2 + 2x + 2ky + 6 = 0` and `x^2 + y^2 + 2ky + k = 0` intersect orthogonally, then k is equal to _____

A

2 or -3/2

B

-2 or -3/2

C

2 or 3/2

D

-2 or 3/2

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The correct Answer is:
A
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