Home
Class 11
MATHS
We are required to from different words ...

We are required to from different words with the help of the letter of the word INTEGER. Let `m_1` be the number of words in which I and N are never together and `m_2` be the number of words which beginning with I and end with R, then `m_1/m_2` is given by

A

42

B

30

C

6

D

44226

Text Solution

Verified by Experts

The correct Answer is:
B
Promotional Banner

Topper's Solved these Questions

  • PARABOLA, ELLIPSE AND HYPERBOLA

    PATHFINDER|Exercise QUESTION BANK|66 Videos
  • PERMUTATION AND COMBINATIONS

    PATHFINDER|Exercise QUESTION BANK|81 Videos

Similar Questions

Explore conceptually related problems

Consider the letters of the word 'MATHEMATICS Possible numbers of words in which no two vowels are together is -

The number of ways in which the letters of the word ARRANGE be arranged so that the two R's are never together.

Different words are being formed by arranging the letters of the words 'ARRANGE'. All the words obtained are written in the form of a dictionary. The number of words in which the two 'R' are not together

Find the number of arrangements of the letters of the word INDEPENDENCE. In how many of these arrangements. do the words begin with I and end in P ?

Number of words that can be made with the letters of the word "GENIUS" if each word neither begins with G nor ends in S is

Different words are being formed by arranging the letters of the word "SUCCESS" all the words obtained by written in the form of a dictionary The number of words in which no two C's and no two S's are together is

Find the number of different arrangements with the letters of the word 'ALGEBRA' so that the two A'a are not together?

Find the number of arrangements of the letters of the word INDEPENDENCE. In how many of these arrangements, do the words begin with I and end in P?

Different words are being formed by arranging the letters of the words 'AARANGE'. All the words obtained are written in the form of a dictionary. The number of words in which neither two 'R' nor two 'A' come together is

The number of ways in which the letters of the word ARRANGE can be permuted such that the R's occur together is

PATHFINDER-PERMUTATION AND COMBINATION-QUESTION BANK
  1. The number of divisors of 2^2 cdot 3^3 cdot 5^5 cdot 7^5 of the form 4...

    Text Solution

    |

  2. The maximum number of different permutations of 4 letters of the word ...

    Text Solution

    |

  3. We are required to from different words with the help of the letter of...

    Text Solution

    |

  4. The number of polynomials of the form x^3 + ax^2 + bx + c which are di...

    Text Solution

    |

  5. A closet has 5 pairs of shoes. The number of ways in which 4 shoes can...

    Text Solution

    |

  6. The number of positive integers satisfying the inequality .^(n+1)C(n-2...

    Text Solution

    |

  7. A father with 8 children takes 3 at a time to the zoological gardens, ...

    Text Solution

    |

  8. For 2 le r le n,(n/r) + 2(n/(r-1)) + (n/(r - 2)) is equal to

    Text Solution

    |

  9. A letter lock consists of three rings marked with 15 different letters...

    Text Solution

    |

  10. The number of subsets of a set containing n distinct elements is

    Text Solution

    |

  11. If alpha = x1x2x3 and beta = y1y2y3 be two three digits numbers , the ...

    Text Solution

    |

  12. The number of diagonals an n - sided convex polygon is

    Text Solution

    |

  13. 24! is divisible by

    Text Solution

    |

  14. If N is the number of positive integral solutions of x1 cdot x2 cdot x...

    Text Solution

    |

  15. The total number of ways in which a beggar can be given at least one r...

    Text Solution

    |

  16. The number of ways in which three numbers in A.P. can be selected from...

    Text Solution

    |

  17. If n lt p lt 2n and p is prime and N = .^(2n)Cn, then

    Text Solution

    |

  18. Let vec a = vec i + vec j + vec k and let vec r be a variable vector s...

    Text Solution

    |

  19. 2^m3^n5^p is a divisor of 2^10 cdot 3^8 cdot 5^7 if m, n and p are all...

    Text Solution

    |

  20. 2^m3^n5^p is a divisor of 2^10 cdot 3^8 cdot 5^7 if m, n and p are all...

    Text Solution

    |