`2^m3^n5^p` is a divisor of `2^10 cdot 3^8 cdot 5^7` if m, n and p are all whole number such that `0 le m le 10, 0 le n le 8` and `0 le p le 7`. also,
`(2^0 + 2^1 +.........+2^10)(3^0 + 3^1 +.......+3^8)(5^0+5^1+....+5^7)` = sum of all the divisors of `2^10 cdot 3^8 cdot 5^7`
The number of proper divisors of 16200 is

Options

A. 60
B. 24
C. 58
D. 22

Answer

C