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Let A =(x1,x2,x3,x4,x5,x6}B={y1,y2,y3,y4...

Let `A =(x_1,x_2,x_3,x_4,x_5,x_6}B={y_1,y_2,y_3,y_4,y_5,y_6}` then the number of one one mappings from A to B such that `f(x_!)ney_i ,i=1,2,3,4,5,6` is

A

720

B

265

C

360

D

145

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The correct Answer is:
B
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