(10!)=(2)^p.(3)^q.(5)^r.(7)^8 then...

`(10!)=(2)^p.(3)^q.(5)^r.(7)^8` then

2q=p

pqrs=64

number of divisors of `10!` is 280

number of ways of putting `10!` as a product of two natural numbers is 135

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B, C, D

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