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f(x)=x^5/5-8/3x^3+(16+c)x, then find the...

`f(x)=x^5/5-8/3x^3+(16+c)x`, then find the range of c, so that function is one-one function.

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`f(x)=x^5/5-8/3x^3+(16+c)x`
`f.(x)=x^4-8x^2+16+c`
`=(x^2-4)^2+c`
f(x) is one-one function `f.(x)ge0 implies c ge 0`
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