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Let f:[-pi/3, 2pi/3] rarr [0,4] be a fun...

Let `f:[-pi/3, 2pi/3] rarr [0,4]` be a function defined as `f(x)=sqrt3 sinx-cosx+2`. Then `f^-1(x)` is given by

A

`sin^-1((x-2)/2)-pi/6`

B

`sin^-1((x+2)/2)+pi/6`

C

`2pi/3 - cos^-1((x-2)/2)`

D

none of these

Text Solution

Verified by Experts

The correct Answer is:
C
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