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If f(x)=x/(x^2+1) and f(A)={y:-1/2 le y ...

If `f(x)=x/(x^2+1)` and `f(A)={y:-1/2 le y lt 0}`, then set A is

A

`[-1,0)`

B

`(-oo,-1]`

C

`(-oo,0)`

D

`(- oo, oo)`

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