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f(x)=sqrt([sin2x]-[cos2x]) :[.]GIF, then...

`f(x)=sqrt([sin2x]-[cos2x])` :[.]GIF, then range of f(x)

A

{0}

B

{1}

C

{0, 1}

D

`{0,1,sqrt2}`

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The correct Answer is:
A
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