Let (x) `f_1(x)-2f_2(x)`
where `f_1(x) = "min"{x^2, |x|} "for"-1 le x le 1`
max`{x^2, |x| "for" |x| gt 1`
`f_2(x)= "max" {x^2, |x|} "for" -1 le x le 1`
min `{x^2, |x|} for |x| gt 1`
`g(x) = {(min{f(t) : -3 le t le x, -3 le x le o}),(max{f(t) : 0 le t le x, 0 le x le 3}):}
Answer the following question based on above passage :
For `-3 le x le -1`, range of g(x) is

Options

A. [-1, 3]
B. [-1 + 15]
C. [-1, 9]
D. None of these

Answer

A