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Let a,b,c,d, e ar non-zero and distinct ...

Let a,b,c,d, e ar non-zero and distinct positive real numbers. If a,b, c are In a,b,c are in A.B, b,c, dare in G.P. and c,d e are in H.P, the a,c,e are in :

A

A.P.

B

G.P.

C

H.P.

D

Nothing can be said

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The correct Answer is:
To solve the problem step by step, we will analyze the given conditions and derive the necessary relationships. **Step 1: Understand the given conditions.** We have three sequences: 1. \( a, b, c \) are in Arithmetic Progression (AP). 2. \( b, c, d \) are in Geometric Progression (GP). 3. \( c, d, e \) are in Harmonic Progression (HP). **Step 2: Use the definition of AP for \( a, b, c \).** Since \( a, b, c \) are in AP, we can express this as: \[ b = \frac{a + c}{2} \tag{1} \] **Step 3: Use the definition of GP for \( b, c, d \).** Since \( b, c, d \) are in GP, we can express this as: \[ c^2 = bd \tag{2} \] **Step 4: Use the definition of HP for \( c, d, e \).** Since \( c, d, e \) are in HP, we can express this as: \[ d = \frac{2ce}{c + e} \tag{3} \] **Step 5: Substitute equations (1) and (3) into equation (2).** From equation (1), we have \( b = \frac{a + c}{2} \). Substitute this into equation (2): \[ c^2 = \left(\frac{a + c}{2}\right) d \] Now, substitute \( d \) from equation (3): \[ c^2 = \left(\frac{a + c}{2}\right) \left(\frac{2ce}{c + e}\right) \] This simplifies to: \[ c^2 = \frac{(a + c) ce}{c + e} \] **Step 6: Cross-multiply to eliminate the fraction.** Cross-multiplying gives: \[ c^2(c + e) = (a + c) ce \] Expanding both sides: \[ c^3 + c^2 e = ace + c e^2 \] **Step 7: Rearranging the equation.** Rearranging gives: \[ c^3 - ace + c^2 e - c e^2 = 0 \] **Step 8: Factor out common terms.** We can factor out \( c \): \[ c(c^2 - ae + ce - e^2) = 0 \] Since \( c \) is non-zero, we can ignore this factor: \[ c^2 - ae + ce - e^2 = 0 \] **Step 9: Rearranging to find the relationship between \( a, c, e \).** This leads us to: \[ c^2 = ae \] This is the condition for \( a, c, e \) to be in Geometric Progression (GP). **Conclusion:** Since we have derived that \( c^2 = ae \), we conclude that \( a, c, e \) are in Geometric Progression (GP). **Final Answer:** \( a, c, e \) are in GP. ---
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VIKAS GUPTA (BLACK BOOK) ENGLISH-SEQUENCE AND SERIES -EXERCISE (SUBJECTIVE TYPE PROBLEMS)
  1. Let a,b,c,d, e ar non-zero and distinct positive real numbers. If a,b,...

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  2. Let a,b,c,d be four distinct real number in A.P.Then the smallest posi...

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  3. The sum of all digits of n for which sum (r =1) ^(n ) r 2 ^(r ) = 2+2^...

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  4. If lim ( n to oo) (r +2)/(2 ^(r+1) r (r+1))=1/k, then k =

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  5. The value of sum (r =1) ^(oo) (8r)/(4r ^(4) +1) is equal to :

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  6. If three non-zero distinct real numbers form an arithmatic progression...

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  7. The sum of the fourth and twelfth term of an arithmetic progression is...

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  8. In an increasing sequence of four positive integers, the first 3 terms...

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  9. The limit of (1)/(n ^(4)) sum (k =1) ^(n) k (k +2) (k +4) as n to oo i...

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  10. Which is the last digit of 1+2+3+……+ n if the last digit of 1 ^(3) + ...

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  11. There distinct positive numbers, a,b,c are in G.P. while log (c) a, lo...

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  12. The numbers 1/3, 1/3 log (x) y, 1/3 log (y) z, 1/7 log (x) x are in H...

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  13. If sum ( k =1) ^(oo) (k^(2))/(3 ^(k))=p/q, where p and q are relativel...

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  14. The sum of the terms of an infinitely decreassing Geometric Progressio...

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  15. A cricketer has to score 4500 runs. Let a (n) denotes the number of ru...

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  16. If x=10 sum(r=3) ^(100) (1)/((r ^(2) -4)), then [x]= (where [.] deno...

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  17. Let f (n)=(4n + sqrt(4n ^(2) -1))/( sqrt(2n +1 )+sqrt(2n-1)),n in N th...

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  18. Find the sum of series 1+1/2+1/3+1/4+1/6+1/8+1/9+1/12+…… oo, where the...

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  19. Let a (1), a(2), a(3),…….., a(n) be real numbers in arithmatic progres...

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  20. Let the roots of the equation 24 x ^(3) -14x ^(2) + kx +3=0 form a geo...

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  21. How many ordered pair (s) satisfy log (x ^(3) + (1)/(3) y ^(3) + (1)/(...

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