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For Delta ABC, if 81 + 144 a ^(4) + 16b...

For `Delta ABC, ` if `81 + 144 a ^(4) + 16b ^(4) + 9c ^(4) =144` abc, (where notations have their usual meaning), then :

A

`a gt b gt c`

B

`A lt B lt C`

C

Area of `Delta ABC = (3 sqrt3)/(8)`

D

Triangle ABC is right angled

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To solve the problem, we start with the equation given for triangle ABC: \[ 81 + 144a^4 + 16b^4 + 9c^4 = 144abc \] ### Step 1: Rearranging the Equation First, we can rearrange the equation to isolate the terms on one side: \[ 144a^4 + 16b^4 + 9c^4 - 144abc + 81 = 0 \] ### Step 2: Recognizing Powers Next, we can rewrite some of the terms to see if we can simplify the expression. Notice that: - \( 81 = 3^4 \) - \( 144 = (12)^2 \) - \( 16 = (4)^2 \) - \( 9 = (3)^2 \) Thus, we can express the equation as: \[ 3^4 + (12a)^4 + (4b)^4 + (3c)^4 = 144abc \] ### Step 3: Applying the AM-GM Inequality We can apply the Arithmetic Mean-Geometric Mean (AM-GM) inequality here. The AM-GM states that for non-negative numbers, the arithmetic mean is greater than or equal to the geometric mean. We have four terms: 1. \( 3^4 \) 2. \( (12a)^4 \) 3. \( (4b)^4 \) 4. \( (3c)^4 \) According to AM-GM: \[ \frac{3^4 + (12a)^4 + (4b)^4 + (3c)^4}{4} \geq \sqrt[4]{3^4 \cdot (12a)^4 \cdot (4b)^4 \cdot (3c)^4} \] ### Step 4: Finding the Geometric Mean Calculating the geometric mean: \[ \sqrt[4]{3^4 \cdot (12a)^4 \cdot (4b)^4 \cdot (3c)^4} = 3 \cdot 12a \cdot 4b \cdot 3c \] ### Step 5: Equating AM and GM Since we have equality in AM-GM when all terms are equal, we set: \[ 3 = 12a = 4b = 3c \] ### Step 6: Solving for a, b, and c From \( 12a = 3 \): \[ a = \frac{3}{12} = \frac{1}{4} \] From \( 4b = 3 \): \[ b = \frac{3}{4} \] From \( 3c = 3 \): \[ c = 1 \] ### Step 7: Checking the Triangle Inequality We need to check if the values satisfy the triangle inequality: 1. \( a + b > c \) → \( \frac{1}{4} + \frac{3}{4} > 1 \) (True) 2. \( a + c > b \) → \( \frac{1}{4} + 1 > \frac{3}{4} \) (True) 3. \( b + c > a \) → \( \frac{3}{4} + 1 > \frac{1}{4} \) (True) All inequalities hold, so \( a, b, c \) can form a triangle. ### Step 8: Determining Angles The angles opposite to sides \( a, b, c \) can be compared since \( a < b < c \) implies \( \angle A < \angle B < \angle C \). ### Step 9: Area of Triangle To find the area, we can use Heron's formula or the formula for a right triangle if applicable. Since we have determined the sides, we can check if it is a right triangle using Pythagoras theorem. ### Conclusion From the calculations, we conclude: 1. The order of sides is \( a < b < c \). 2. The angles follow the same order. 3. The area can be calculated using the appropriate formula.
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