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If 2 cos theta + sin theta =1 then ...

If `2 cos theta + sin theta =1 then `7 cos theta + 6 sin theta` is equal to

A

1 or 2

B

2 or 3

C

2 or 4

D

2 or 6

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To solve the problem, we need to find the value of \( 7 \cos \theta + 6 \sin \theta \) given that \( 2 \cos \theta + \sin \theta = 1 \). ### Step-by-Step Solution: 1. **Start with the given equation:** \[ 2 \cos \theta + \sin \theta = 1 \] 2. **Rearrange the equation:** \[ 2 \cos \theta = 1 - \sin \theta \] 3. **Square both sides:** \[ (2 \cos \theta)^2 = (1 - \sin \theta)^2 \] This gives: \[ 4 \cos^2 \theta = 1 - 2 \sin \theta + \sin^2 \theta \] 4. **Use the Pythagorean identity \( \cos^2 \theta = 1 - \sin^2 \theta \):** \[ 4(1 - \sin^2 \theta) = 1 - 2 \sin \theta + \sin^2 \theta \] Expanding this gives: \[ 4 - 4 \sin^2 \theta = 1 - 2 \sin \theta + \sin^2 \theta \] 5. **Rearranging the equation:** \[ 4 - 1 = 4 \sin^2 \theta + \sin^2 \theta - 2 \sin \theta \] This simplifies to: \[ 3 = 5 \sin^2 \theta - 2 \sin \theta \] Rearranging gives: \[ 5 \sin^2 \theta - 2 \sin \theta - 3 = 0 \] 6. **Factor the quadratic equation:** \[ (5 \sin \theta + 3)(\sin \theta - 1) = 0 \] This gives us two possible solutions: \[ \sin \theta = 1 \quad \text{or} \quad 5 \sin \theta + 3 = 0 \Rightarrow \sin \theta = -\frac{3}{5} \] 7. **Find \( \cos \theta \) for both cases:** - For \( \sin \theta = 1 \): \[ \cos \theta = 0 \] - For \( \sin \theta = -\frac{3}{5} \): \[ \sin^2 \theta + \cos^2 \theta = 1 \Rightarrow \left(-\frac{3}{5}\right)^2 + \cos^2 \theta = 1 \] \[ \frac{9}{25} + \cos^2 \theta = 1 \Rightarrow \cos^2 \theta = 1 - \frac{9}{25} = \frac{16}{25} \Rightarrow \cos \theta = \frac{4}{5} \text{ or } -\frac{4}{5} \] 8. **Calculate \( 7 \cos \theta + 6 \sin \theta \) for both cases:** - For \( \sin \theta = 1 \) and \( \cos \theta = 0 \): \[ 7 \cos \theta + 6 \sin \theta = 7(0) + 6(1) = 6 \] - For \( \sin \theta = -\frac{3}{5} \) and \( \cos \theta = \frac{4}{5} \): \[ 7 \cos \theta + 6 \sin \theta = 7\left(\frac{4}{5}\right) + 6\left(-\frac{3}{5}\right) = \frac{28}{5} - \frac{18}{5} = \frac{10}{5} = 2 \] ### Final Answer: Thus, the values of \( 7 \cos \theta + 6 \sin \theta \) can be \( 6 \) or \( 2 \). The answer is \( 2 \).
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VIKAS GUPTA (BLACK BOOK) ENGLISH-COMPOUND ANGLES-Exercise-5 : Subjective Type Problems
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