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In triangle A B C ,/B=pi/3,a n d/C=pi/4d...

In triangle `A B C ,/_B=pi/3,a n d/_C=pi/4dot` Let `D` divided `B C` internally in the ratio `1: 3.` Then`(sin/_B A D)/(sin/_C A D)` equals (a)`1/(sqrt(6))` (b) `1/3` (c) `1/(sqrt(3))` (d) `sqrt(2/3)`

A

`(1)/(sqrt(6))`

B

`(1)/(3)`

C

`(1)/(sqrt(3))`

D

`(sqrt(2))/(3)`

Text Solution

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A
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