Select correct statement(s) is /are :

Options

A. In `AsH_(3)` molecule lone pair at central atom is present in almost pure s-orbital
B. Number of `p pi -d pi` bond in `SO_(3) and SO_(2)` are same
C. `NF_(3)` is better Lewis base than `NCl_(3)`
D. Stable oxidation state of Lead is `+2`

Explanation

To solve the question, we need to evaluate each statement provided and determine which ones are correct. Let's analyze each statement step by step.

### Step-by-Step Solution:

**Step 1: Analyze Statement A**
- Statement A: "In a SH3 molecule, the lone pair at the central atom is present in almost pure s orbital."
- Analysis: The central atom in SH3 (which is similar to NH3) is sulfur (S). Sulfur has the electronic configuration of [Ne]3s²3p⁴. In SH3, one of the 3s electrons forms a bond with hydrogen, and the remaining lone pair is indeed in the 3s orbital. Therefore, this statement is **correct**.

**Step 2: Analyze Statement B**
- Statement B: "The number of pπ-dπ bonds in SO3 and SO2 are the same."
- Analysis: In SO2, sulfur forms one pπ-dπ bond and one pπ-pπ bond with oxygen. In SO3, sulfur forms two pπ-dπ bonds and one pπ-pπ bond. Therefore, the number of pπ-dπ bonds in SO2 and SO3 are not the same. This statement is **incorrect**.

**Step 3: Analyze Statement C**
- Statement C: "NF3 is a better Lewis base than NCl3."
- Analysis: A Lewis base is defined as a species that can donate a pair of electrons. In NF3, the electronegativity of fluorine is higher than that of chlorine, which means fluorine pulls electron density away from nitrogen, making the lone pair less available for donation. In contrast, in NCl3, the chlorine atoms are less electronegative and do not withdraw electron density as strongly, making the lone pair more available for donation. Thus, NCl3 is a better Lewis base than NF3. This statement is **incorrect**.

**Step 4: Analyze Statement D**
- Statement D: "The stable oxidation state of lead is +2."
- Analysis: Lead (Pb) belongs to the carbon family. As we move down the group, the +2 oxidation state becomes more stable compared to the +4 oxidation state. Therefore, the stable oxidation state of lead is indeed +2. This statement is **correct**.

### Conclusion:
The correct statements are:
- Statement A: Correct
- Statement B: Incorrect
- Statement C: Incorrect
- Statement D: Correct

Thus, the correct answers are **A and D**.