`C_2H_2` is isostructural with

Options

A. `H_(2)O_(2)`
B. `NO_(2)`
C. `SnCl_(2)`
D. `CO_(2)`

Answer

To determine which compound is isostructural with \( C_2H_2 \) (ethyne), we need to analyze the structure and hybridization of \( C_2H_2 \) and compare it with the given options.

### Step-by-Step Solution:

1. **Identify the Structure of \( C_2H_2 \)**:
- The molecular formula \( C_2H_2 \) corresponds to ethyne, which has a triple bond between the two carbon atoms.
- The structure can be represented as \( H-C \equiv C-H \).

2. **Determine the Hybridization of Carbon in \( C_2H_2 \)**:
- Each carbon atom in \( C_2H_2 \) is involved in one sigma bond with hydrogen and one sigma bond with the other carbon, while the triple bond consists of one sigma bond and two pi bonds.
- The hybridization can be calculated as follows:
- Number of sigma bonds = 2 (one with hydrogen and one with another carbon)
- Number of lone pairs = 0
- Hybridization index = Number of sigma bonds + Number of lone pairs = 2 + 0 = 2.
- Therefore, the hybridization of each carbon in \( C_2H_2 \) is \( sp \).

3. **Determine the Shape of \( C_2H_2 \)**:
- Compounds with \( sp \) hybridization have a linear geometry.
- Thus, \( C_2H_2 \) is linear.

4. **Analyze the Given Options**:
- **Hydrogen Peroxide \( H_2O_2 \)**: Has a non-linear structure (open book-like).
- **Nitrogen Dioxide \( NO_2 \)**: Has \( sp^2 \) hybridization and a bent shape (non-linear).
- **Tin Chloride \( SnCl_2 \)**: Has \( sp^2 \) hybridization and a bent shape (non-linear).
- **Carbon Dioxide \( CO_2 \)**: Has \( sp \) hybridization and is linear.

5. **Conclusion**:
- The only compound that is linear and has \( sp \) hybridization, just like \( C_2H_2 \), is \( CO_2 \).
- Therefore, \( C_2H_2 \) is isostructural with \( CO_2 \).

### Final Answer:
\( C_2H_2 \) is isostructural with \( CO_2 \).

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