In terms of polar character the correct, the correct order is .

Options

A. `NH_(3)ltH_(2)OgtHFltH_(2)S`
B. `H_(2)SltNH_(3)ltH_(2)OltHF`
C. `H_(2)OltNH_(3)ltH_(2)SltHF`
D. `HFltH_(2)OltNH_(3)ltH_(2)O`

Explanation

To determine the correct order of polar character among the given compounds (NH3, H2O, HF, and H2S), we need to analyze their molecular structures and the electronegativities of the atoms involved. Here’s a step-by-step solution:

### Step 1: Understand Polar Character
Polar character in a molecule arises due to the difference in electronegativity between the bonded atoms. The greater the difference, the more polar the bond.

### Step 2: Identify the Compounds
The compounds we are analyzing are:
1. NH3 (Ammonia)
2. H2O (Water)
3. HF (Hydrogen Fluoride)
4. H2S (Hydrogen Sulfide)

### Step 3: Determine Electronegativity Values
Next, we need to look up the electronegativity values of the relevant atoms:
- Fluorine (F): 4.0
- Oxygen (O): 3.5
- Nitrogen (N): 3.0
- Sulfur (S): 2.5

### Step 4: Analyze Each Compound
1. **HF**: The bond between H and F has a large electronegativity difference (4.0 - 2.1 = 1.9), making HF highly polar.
2. **H2O**: The bond between H and O also has a significant difference (3.5 - 2.1 = 1.4), making H2O polar but less so than HF.
3. **NH3**: The bond between H and N has a difference of (3.0 - 2.1 = 0.9), making NH3 polar but less so than H2O.
4. **H2S**: The bond between H and S has a difference of (2.5 - 2.1 = 0.4), making H2S the least polar of the four.

### Step 5: Establish the Order of Polar Character
Based on the electronegativity differences, we can establish the order of polar character:
1. HF (most polar)
2. H2O
3. NH3
4. H2S (least polar)

Thus, the correct order in terms of polar character is:
**HF > H2O > NH3 > H2S**

### Final Answer
The correct order of polar character is: **HF > H2O > NH3 > H2S**

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