The comcept of redistribution of energy in different orbitals of an atom associated with different energies to give new orbitals of equal (or somethimes it may be non-equal) energy oriented in space in definite directions is called hybridization and formed new orbitals are called hybrid orbitals. The bonds formed by such orbitals are called hybrid bonds. The process of mixing of orbitals itself requires some energy. Thus, some additional energy, is needed for the hybridisation (mixing) of atomic orbitals.
Q. In neutral moleule `XeO_(n_(1)) F_(n_(2))`, central atom has no lone pair and ratio of `(n_(2))/(n_(1))` is two, then which of the following orbitals does not participate in bonding (`n_(1) and n_(2)` are natural numbers):

Options

A. `d_(x^(2))`
B. `p_(x)`
C. `d_(x^(2)-y^(2))`
D. None of these

Answer

D

Explanation

For `XeO_(2)F_(4)=(n_(2))/(n_(1))=1`
Hyb. Of Xe:`sp^(3)d^(2)[sp_(x)p_(y)p_(z)d_(x^(2)-y^(2))d_(z^(2))]`