According to hybridisation theory, the % s-character in `sp, sp^(2) and sp^(3)` hybrid orbitals is 50, 33.3 and 25 respectively, but this is not true for all the species. When `theta` is the bond angle between equivalent hybrid orbitals then % s and p-character in hybrid orbitals (when only s and p-orbitals are involved in hybridisation) can be calculated by the following formula :
`costheta=(S)/(S-1)=(P-1)/(P)`
Q. Two elements X and Y combined together to form a covalent compound. If % p-character is found to be 80% in a orbital then the hybridised state of central atom X for the orbital is :

Options

A. `sp^(2)`
B. `sp^(3)`
C. `sp^(4)`
D. `sp^(5)`

Answer

C