Home
Class 12
CHEMISTRY
The molecule in which an atom is associa...

The molecule in which an atom is associated with more than 8 electrons is known as hypervalent molecule and less than 8 electrons is known as hypovalent molecule. All hypervalent molecules must have `ppi-dpi` bonding but the molecules having back bonding back boding need not to have always `ppi-dpi` bondin.
Q.Which of the following molecule is not having `ppi-dpi` bonding:

A

`SO_(2)`

B

`P_(4)O_(10)`

C

`PF_(3)`

D

`B_(3)N_(3)H_(6)`

Text Solution

AI Generated Solution

The correct Answer is:
To determine which of the given molecules does not have p-pi d-pi bonding, we will analyze each option step by step. ### Step 1: Analyze SO2 - **Valence Electrons**: Sulfur (S) has 6 valence electrons. - **Structure**: In SO2, sulfur forms two sigma bonds with oxygen and has one lone pair. - **Bonding**: The pi bonds involve: - One p-pi p-pi overlap (between sulfur and oxygen). - One p-pi d-pi overlap (between sulfur and oxygen). - **Conclusion**: SO2 has p-pi d-pi bonding. ### Step 2: Analyze P4O10 - **Valence Electrons**: Phosphorus (P) has 5 valence electrons and there are 10 oxygen atoms. - **Structure**: Each phosphorus atom forms 5 bonds (4 sigma and 1 pi). - **Bonding**: The pi bond involves: - p-pi d-pi overlap (between phosphorus and oxygen). - **Conclusion**: P4O10 has p-pi d-pi bonding. ### Step 3: Analyze PF3 - **Valence Electrons**: Phosphorus has 5 valence electrons, and each fluorine has 7. - **Structure**: In PF3, phosphorus forms three sigma bonds with fluorine. - **Bonding**: The pi bond involves: - p-pi d-pi overlap (between phosphorus and fluorine). - **Conclusion**: PF3 has p-pi d-pi bonding. ### Step 4: Analyze B3N3H6 (Inorganic Benzene) - **Valence Electrons**: Boron (B) has 3 valence electrons and nitrogen (N) has 5. - **Structure**: The structure alternates between boron and nitrogen atoms, forming a cyclic compound. - **Bonding**: The pi bonds are formed by: - p-pi p-pi overlap (between boron and nitrogen). - **Conclusion**: B3N3H6 does not have p-pi d-pi bonding, as boron and nitrogen do not have d-orbitals. ### Final Conclusion The molecule that does not have p-pi d-pi bonding is **B3N3H6**. ---
Promotional Banner

Topper's Solved these Questions

  • CHEMICAL BONDING (ADVANCED)

    VK JAISWAL ENGLISH|Exercise ONE OR MORE ANSWER IS/ARE CORRECT|78 Videos
  • CHEMICAL BONDING (ADVANCED)

    VK JAISWAL ENGLISH|Exercise MATCH THE COLUMN|21 Videos
  • CHEMICAL BONDING (ADVANCED)

    VK JAISWAL ENGLISH|Exercise Level 2|150 Videos
  • CHEMICAL BONDING (BASIC)

    VK JAISWAL ENGLISH|Exercise SUBJECTIVE PROBLEMS|54 Videos
VK JAISWAL ENGLISH-CHEMICAL BONDING (ADVANCED)-Level 3
  1. The molecule in which an atom is associated with more than 8 electrons...

    Text Solution

    |

  2. The molecule in which an atom is associated with more than 8 electrons...

    Text Solution

    |

  3. The molecule in which an atom is associated with more than 8 electrons...

    Text Solution

    |

  4. Colour of compounds occurs due to phenomenon of polarisation, charge t...

    Text Solution

    |

  5. Hydrogen bond is the given to the relatively weak secondry interaction...

    Text Solution

    |

  6. Hydrogen bond is the given to the relatively weak secondry interaction...

    Text Solution

    |

  7. The intermolecular forces of attraction (i.e., H-bonding and van der w...

    Text Solution

    |

  8. The intermolecular forces of attraction (i.e., H-bonding and van der w...

    Text Solution

    |

  9. The intermolecular forces of attraction (i.e., H-bonding and van der w...

    Text Solution

    |

  10. In all expected compounds each central atom only uses its s and p-orbi...

    Text Solution

    |

  11. The comcept of redistribution of energy in different orbitals of an at...

    Text Solution

    |

  12. The comcept of redistribution of energy in different orbitals of an at...

    Text Solution

    |

  13. The comcept of redistribution of energy in different orbitals of an at...

    Text Solution

    |

  14. Drago suggested an emprical rule which is compatible with the energeti...

    Text Solution

    |

  15. Drago suggested an emprical rule which is compatible with the energeti...

    Text Solution

    |

  16. According to hybridisation theory, the % s-character in sp, sp^(2) and...

    Text Solution

    |

  17. According to hybridisation theory, the % s-character in sp, sp^(2) and...

    Text Solution

    |

  18. According to hybridisation theory, the % s-character in sp, sp^(2) and...

    Text Solution

    |

  19. PCl(5) is an example of a molecule having sp^(3)d-hybridisation. Three...

    Text Solution

    |

  20. PCl(5) is an example of a molecule having sp^(3)d-hybridisation. Three...

    Text Solution

    |