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Which of the following equlibria would h...

Which of the following equlibria would have highest and lowest value of `K_(p)` at a commone temperature?

A

`BeCO_(3) to BeO+CO_(2)`

B

`CaCO_(3) to CaO+CO_(2)`

C

`SrCO_(3) to SrO+CO_(2)`

D

`BaCO_(3) to BaO+CO_(2)`

Text Solution

AI Generated Solution

The correct Answer is:
To determine which of the given equilibria has the highest and lowest value of \( K_p \) at a common temperature, we need to analyze the stability of the carbonates of alkaline earth metals involved in the reactions. The reactions given are: 1. Beryllium carbonate (\( BeCO_3 \)) decomposing to beryllium oxide (\( BeO \)) and carbon dioxide (\( CO_2 \)). 2. Calcium carbonate (\( CaCO_3 \)) decomposing to calcium oxide (\( CaO \)) and carbon dioxide (\( CO_2 \)). 3. Strontium carbonate (\( SrCO_3 \)) decomposing to strontium oxide (\( SrO \)) and carbon dioxide (\( CO_2 \)). 4. Barium carbonate (\( BaCO_3 \)) decomposing to barium oxide (\( BaO \)) and carbon dioxide (\( CO_2 \)). ### Step 1: Understand Stability of Carbonates The stability of alkaline earth metal carbonates (\( MCO_3 \)) increases down the group in the periodic table. This means that: - \( BeCO_3 \) is the least stable. - \( BaCO_3 \) is the most stable. ### Step 2: Relate Stability to \( K_p \) The equilibrium constant \( K_p \) is inversely related to the stability of the compound. This means: - The less stable the compound, the higher the value of \( K_p \) because it decomposes more readily. - The more stable the compound, the lower the value of \( K_p \) because it does not decompose easily. ### Step 3: Analyze Each Compound - **Beryllium Carbonate (\( BeCO_3 \))**: Least stable → Highest \( K_p \) - **Calcium Carbonate (\( CaCO_3 \))**: More stable than \( BeCO_3 \) → Lower \( K_p \) than \( BeCO_3 \) - **Strontium Carbonate (\( SrCO_3 \))**: More stable than \( CaCO_3 \) → Lower \( K_p \) than \( CaCO_3 \) - **Barium Carbonate (\( BaCO_3 \))**: Most stable → Lowest \( K_p \) ### Conclusion From the analysis: - **Highest \( K_p \)**: Beryllium carbonate (\( BeCO_3 \)) - **Lowest \( K_p \)**: Barium carbonate (\( BaCO_3 \)) ### Final Answer - Highest \( K_p \): Beryllium carbonate (\( BeCO_3 \)) - Lowest \( K_p \): Barium carbonate (\( BaCO_3 \)) ---
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