Which of the following molecule has as `O_O` bonds?

Options

A. `H_(2)S_(2)O_(8)`
B. `H_(2)S_(2)O_(7)`
C. `H_(2)SO_(5)`
D. `H_(2)S_(2)O_(6)`

Answer

To determine which of the given molecules has an O-O bond, we will analyze each option by drawing their structures and identifying the presence of the O-O bond.

### Step-by-Step Solution:

1. **Identify the Compounds:**
The compounds given are:
- Option 1: H2S2O8
- Option 2: H2S2O7
- Option 3: H2SO5
- Option 4: H2S2O6

2. **Draw the Structure of H2S2O8:**
- Sulfur can form a maximum of 6 bonds.
- In H2S2O8, there are 2 hydrogen atoms, which means 2 hydroxyl (OH) groups attached to sulfur.
- Each sulfur atom forms double bonds with 4 oxygen atoms.
- The remaining bond from one sulfur can form a peroxide linkage with the other sulfur, resulting in an O-O bond.
- **Conclusion:** H2S2O8 has an O-O bond.

3. **Draw the Structure of H2S2O7:**
- Similar to the previous molecule, each sulfur forms one OH group.
- Each sulfur forms double bonds with two oxygen atoms.
- There is one oxygen atom lying between the two sulfur atoms, but there is no O-O bond present.
- **Conclusion:** H2S2O7 does not have an O-O bond.

4. **Draw the Structure of H2SO5:**
- In H2SO5, two oxygen atoms form double bonds with sulfur, and one oxygen forms a hydroxyl group.
- The remaining oxygen forms a peroxide linkage with another oxygen.
- **Conclusion:** H2SO5 has an O-O bond.

5. **Draw the Structure of H2S2O6:**
- In H2S2O6, there are two sulfur atoms, each with one OH group.
- Each sulfur forms double bonds with two oxygen atoms.
- There is a single bond between the two sulfur atoms, but no O-O bond is present.
- **Conclusion:** H2S2O6 does not have an O-O bond.

### Final Answer:
The molecules that contain O-O bonds are:
- **Option 1: H2S2O8**
- **Option 3: H2SO5**