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Total number of angle in SeCl(4) which a...

Total number of angle in `SeCl_(4)` which are less than `90^(@)`.

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To determine the total number of angles in \( \text{SeCl}_4 \) that are less than \( 90^\circ \), we first need to analyze the molecular geometry of the compound. ### Step 1: Determine the Lewis Structure of \( \text{SeCl}_4 \) 1. **Count the Valence Electrons**: - Selenium (Se) has 6 valence electrons. - Each Chlorine (Cl) has 7 valence electrons, and there are 4 Cl atoms. - Total valence electrons = \( 6 + (4 \times 7) = 6 + 28 = 34 \) electrons. 2. **Draw the Lewis Structure**: - Place Se in the center and surround it with 4 Cl atoms. - Form single bonds between Se and each Cl atom, using 8 electrons (4 bonds). - Distribute the remaining 26 electrons as lone pairs on Cl atoms (3 lone pairs on each Cl). ### Step 2: Determine the Molecular Geometry 1. **Identify the Steric Number**: - The steric number is the number of bonded atoms plus the number of lone pairs around the central atom. - In \( \text{SeCl}_4 \), there are 4 bonded Cl atoms and no lone pairs on Se. - Steric number = \( 4 + 0 = 4 \). 2. **Determine the Geometry**: - A steric number of 4 corresponds to a tetrahedral arrangement of electron pairs. - However, since all bonds are single bonds, the actual molecular shape is also tetrahedral. ### Step 3: Analyze the Bond Angles 1. **Identify Bond Angles**: - In a perfect tetrahedral geometry, the bond angles are \( 109.5^\circ \). - However, due to the presence of lone pairs, the angles can be affected. 2. **Determine Angles Less Than \( 90^\circ \)**: - In a tetrahedral arrangement, the angles between the bonds are typically greater than \( 90^\circ \). - Since there are no lone pairs on the central atom (Se), all angles remain close to \( 109.5^\circ \). ### Conclusion - Since there are no angles in \( \text{SeCl}_4 \) that are less than \( 90^\circ \), the total number of angles in \( \text{SeCl}_4 \) that are less than \( 90^\circ \) is **0**. ### Final Answer **Total number of angles in \( \text{SeCl}_4 \) which are less than \( 90^\circ \) = 0.** ---

To determine the total number of angles in \( \text{SeCl}_4 \) that are less than \( 90^\circ \), we first need to analyze the molecular geometry of the compound. ### Step 1: Determine the Lewis Structure of \( \text{SeCl}_4 \) 1. **Count the Valence Electrons**: - Selenium (Se) has 6 valence electrons. - Each Chlorine (Cl) has 7 valence electrons, and there are 4 Cl atoms. - Total valence electrons = \( 6 + (4 \times 7) = 6 + 28 = 34 \) electrons. ...
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VK JAISWAL ENGLISH-CHEMICAL BONDING (ADVANCED)-SUBJECTIVE PROBLEMS
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