Consider the following compounds:
(i)`IF_(5)` (ii)`ClI_(4)^(-)` (iii)`XeO_(2)F_(2)` (iv)`NH_(2)^(-)` (v) `BCl_(3)` (vi)`BeCl_(2)` (vii)`AsCl_(4)^(+)` (viii)`B(OH)_(3)` (ix)`NO_(2)^(-)` (x)`ClO_(2)^(+)`
Then, calculate value of "`x+y-z`", here x, y and z are total number of compounds in given compounds in which central atom used their all three p-orbitals, only two p-orbitals and only one p-orbital in hybridisation respectively:

Answer

`8`

Explanation

(i)`IF_(5)(sp^(3)d)` (ii)`ClI_(4)^(-)(sp^(3)d^(2)` (iii)`XeO_(2)F_(2)(sp^(3)d` (iv) `NH_(2)^(-)(sp^(3))` (v)`BCl_(3)(sp^(3)` (vi)`BeCl_(2)(sp)` (vii)`AsCl_(4)^(-)` (viii)`(B(OH)_(3)sp^(2)` (ix)`NO_(2)^(-)`
`x=sp^(3)d(2)+sp^(3)d(1)+sp^(3)d^(2)(2)=5`
`y=4, z=1, 4+5-1 implies 8`