Consider the following oxyanions:
`PO_(4)^(3-),P_(2)O_(6)^(4-),SO_(4)^(2-),MnO_(4)^(-),CrO_(4)^(2-),S_(2)O_(5)^(2-),S_(2)O_(7)^(2-)`
and find the value of R+Q-P
where P-number of oxy anions having three equivalent X-O bonds per central atom
Q=number of oxy anions having two equivalent X-O bonds per central atom.
R=Number of oxy anions having four equivalent X-O bonds per central atom.

Answer

`3`

Explanation

`P=2, R=4, Q=1`