`Ba(OH)_(2)+SO_(2) to BaSO_(3)darr+H_(2)O`

Options

A. For coloured ppt./Black ppt
B. For coloured solution.
C. for clear/colourless solution
D. For white ppt.

Answer

To solve the question regarding the reaction between barium hydroxide and sulfur dioxide, we will analyze the reaction step by step.

### Step 1: Write down the reaction
The given reaction is:
\[ \text{Ba(OH)}_2 + \text{SO}_2 \rightarrow \text{BaSO}_3 + \text{H}_2\text{O} \]

### Step 2: Identify the products
In this reaction, barium hydroxide reacts with sulfur dioxide to form barium sulfite (BaSO3) and water (H2O).

### Step 3: Determine the state of the products
- **Barium sulfite (BaSO3)**: This compound is known to be insoluble in water, which means it will precipitate out of the solution.
- **Water (H2O)**: This is a liquid and will remain in the solution.

### Step 4: Analyze the appearance of the products
Since BaSO3 is a precipitate, it will not remain dissolved in the solution. Instead, it will appear as a solid that settles out of the liquid. Barium sulfite is typically white in color.

### Step 5: Conclusion about the solution
Given that BaSO3 precipitates out and is white in color, the solution itself will not be colored or clear. Instead, it will contain a white precipitate of BaSO3.

### Final Answer
The reaction will form a **white precipitate**.

---