If `AB_(4)^(n)` types species are tetrahedral, then which of the following is /are correctly match ?

Options

A. `{:(A,B,n),(Xe,O,0):}`
B. `{:(A,B,n),(Se,F,0):}`
C. `{:(A,B,n),(P,O,-3):}`
D. `{:(A,B,n),(N,H,+1):}`

Answer

To solve the question regarding the tetrahedral geometry of `AB_(4)^(n)` type species, we will analyze each option given in the question step by step.

### Step-by-Step Solution:

1. **Understanding the Tetrahedral Geometry**:
- The general formula `AB_(4)^(n)` indicates that there is one atom A and four atoms of B surrounding it. For the geometry to be tetrahedral, the steric number must be 4, which corresponds to four bond pairs and zero lone pairs.

2. **Analyzing Option 1: Xenon Tetrafluoride (XeF4)**:
- Here, A = Xenon (Xe) and B = Oxygen (O).
- Xenon has 8 valence electrons, and each oxygen forms a double bond, using 8 electrons total (4 O atoms × 2 electrons each).
- The steric number is 4 (4 bond pairs, 0 lone pairs), leading to sp3 hybridization and tetrahedral geometry.
- **Conclusion**: This option is correct.

3. **Analyzing Option 2: Selenium Tetrafluoride (SeF4)**:
- A = Selenium (Se) and B = Fluorine (F).
- Selenium has 6 valence electrons. With 4 fluorine atoms forming single bonds, 4 electrons are used, leaving 2 electrons as a lone pair.
- The steric number is 5 (4 bond pairs, 1 lone pair), leading to sp3d hybridization and a trigonal bipyramidal geometry.
- **Conclusion**: This option is incorrect.

4. **Analyzing Option 3: Phosphorus Trioxide (PO3^3-)**:
- A = Phosphorus (P) and B = Oxygen (O) with a charge of -3.
- Phosphorus has 5 valence electrons. Three oxygens form single bonds, using 3 electrons, and one oxygen forms a double bond, using 2 electrons.
- The steric number is 4 (4 bond pairs, 0 lone pairs), leading to sp3 hybridization and tetrahedral geometry.
- **Conclusion**: This option is correct.

5. **Analyzing Option 4: Ammonium Ion (NH4^+)**:
- A = Nitrogen (N) and B = Hydrogen (H) with a charge of +1.
- Nitrogen has 5 valence electrons. In NH4^+, nitrogen forms 4 single bonds with hydrogen.
- The steric number is 4 (4 bond pairs, 0 lone pairs), leading to sp3 hybridization and tetrahedral geometry.
- **Conclusion**: This option is correct.

### Final Answer:
The correctly matched options are **Option 1 (XeO4), Option 3 (PO3^3-), and Option 4 (NH4^+)**.