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Linear structure is assumed by: (I) NC...

Linear structure is assumed by:
(I) `NCO` (II)`CS_(2)` (III)`overset(+)(N)O_(2)` (IV)Solid `BeH_(2)`

A

all four

B

(II), (III) and (IV)

C

(I), (II) and (III)

D

(II) and (III)

Text Solution

AI Generated Solution

The correct Answer is:
To determine which of the given compounds has a linear structure, we will analyze each option step by step. ### Step 1: Analyze NCO (Cyanate Ion) 1. **Draw the Lewis Structure**: - Nitrogen (N) has 5 valence electrons, Carbon (C) has 4, and Oxygen (O) has 6. - The total number of valence electrons = 5 + 4 + 6 = 15. - The most stable structure involves a triple bond between N and C, and a double bond between C and O, resulting in the structure: N≡C-O. - The negative charge can be placed on the oxygen atom. 2. **Determine the Geometry**: - The N≡C-O structure is linear due to the triple bond between N and C, which does not allow for any angle deviation. ### Step 2: Analyze CS₂ (Carbon Disulfide) 1. **Draw the Lewis Structure**: - Carbon (C) has 4 valence electrons, and each Sulfur (S) has 6. - The total number of valence electrons = 4 + 2(6) = 16. - The structure can be represented as: S=C=S, where carbon is in the center. 2. **Determine the Geometry**: - The S=C=S structure is also linear due to the double bonds on either side of carbon. ### Step 3: Analyze NO₂⁺ (Nitronium Ion) 1. **Draw the Lewis Structure**: - Nitrogen (N) has 5 valence electrons, and each Oxygen (O) has 6. - The total number of valence electrons = 5 + 2(6) - 1 (for the positive charge) = 16. - The structure is drawn as: O=N^+=O, with a double bond between N and each O. 2. **Determine the Geometry**: - The O=N=O structure is linear due to the double bonds, which allows for a 180-degree bond angle. ### Step 4: Analyze BeH₂ (Beryllium Dihydride) 1. **Draw the Lewis Structure**: - Beryllium (Be) has 2 valence electrons, and each Hydrogen (H) has 1. - The total number of valence electrons = 2 + 2(1) = 4. - The structure is represented as: H-Be-H. 2. **Determine the Geometry**: - The H-Be-H structure is bent due to the presence of lone pairs on beryllium, resulting in an angle less than 180 degrees. ### Conclusion From the analysis: - **Linear Structures**: NCO, CS₂, NO₂⁺ - **Non-Linear Structure**: BeH₂ Thus, the compounds that assume a linear structure are **NCO, CS₂, and NO₂⁺**. ### Final Answer The correct options that assume a linear structure are (I) NCO, (II) CS₂, and (III) NO₂⁺.
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VK JAISWAL ENGLISH-CHEMICAL BONDING (ADVANCED)-SUBJECTIVE PROBLEMS
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  2. There are two groups of compounds A and B. Groups A contains three com...

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  4. When B(2)H(4) is allowed to react with following lewis bases, then how...

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  5. Consider the following elements A, B, C and D and their outer electron...

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  6. Consider following four compounds: (i) C(x) O(y) (ii) C(x)O(y+1) ...

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  7. Calculate expression (x+y+z) for diatomic molecules. where x=Total n...

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  8. If Hund rule violate, then find the total number of species among foll...

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  9. Consider the following table Than calculate value of experssion...

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  10. Total number of species among following, in which bond angle is equal...

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  11. Total number of unpaired electrons(s) present in both cationic and an...

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  12. Total number of species which has/ have symmetrical electronic distrib...

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  13. Total number of molecules, in which each covalent bond is comprised of...

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  14. Total number of angle in SeCl(4) which are less than 90^(@).

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  15. Consider the following species O(Me)(2), N(SiH(3))(3), CO, O(SiH(3))(2...

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  16. Total number of molecules which can form H-bond among themselves. Si...

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  17. Consider two covalent compounds AL(n(1)) and BL(n(2)), if central atom...

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  18. Calculate the I-I distance in (Å) for given compound H(2)C(2) I(2) if ...

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  19. There are some arrangements of atomic orbitals which are given below: ...

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  20. Number of hybrid orbital C atoms which have 33% p-character in C(CN)(4...

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  21. Max. no. of equal P-O bonds in P(2)O(7)^(4-) ion is :

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