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The bond length of the S-O bond is maxim...

The bond length of the S-O bond is maximum in which of the following compounds?

A

`SOCl_(2)`

B

`SOBr_(2)`

C

`SOF_(2)`

D

All have same length

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The correct Answer is:
To determine which compound has the maximum S-O bond length, we need to analyze the compounds in question based on the principles of bond length, bond strength, and electronegativity. ### Step-by-Step Solution: 1. **Understanding Bond Length and Bond Strength**: - Bond length is inversely proportional to bond strength. This means that stronger bonds (like triple bonds) have shorter lengths, while weaker bonds (like single bonds) have longer lengths. - Electronegativity plays a crucial role in determining bond length. Higher electronegativity leads to stronger attraction between atoms, resulting in shorter bond lengths. 2. **Analyzing the Compounds**: - We need to consider the compounds that contain S-O bonds, such as SOCl2, SO2, and SOBr2. - Sulfur (S) is in group 16 and has 6 valence electrons. The bonding behavior of sulfur with different atoms (like Cl, O, and Br) will affect the bond length. 3. **Electronegativity Consideration**: - The electronegativity values of the atoms involved are crucial. Fluorine (F) is the most electronegative, followed by chlorine (Cl), and then bromine (Br). - The more electronegative the atom bonded to sulfur, the shorter the bond length due to stronger attraction. 4. **Comparing the Bond Lengths**: - In SOCl2, the S-O bond is influenced by chlorine's electronegativity, which is higher than that of bromine. - In SO2, sulfur is bonded to two oxygen atoms, which are highly electronegative, resulting in shorter bond lengths. - In SOBr2, bromine is the least electronegative of the three, leading to a weaker attraction and thus a longer S-O bond length. 5. **Conclusion**: - Based on the analysis, the S-O bond length will be maximum in SOBr2 due to the larger size and lower electronegativity of bromine compared to chlorine and oxygen. This results in a weaker bond and a longer bond length. ### Final Answer: The S-O bond length is maximum in **SOBr2**.

To determine which compound has the maximum S-O bond length, we need to analyze the compounds in question based on the principles of bond length, bond strength, and electronegativity. ### Step-by-Step Solution: 1. **Understanding Bond Length and Bond Strength**: - Bond length is inversely proportional to bond strength. This means that stronger bonds (like triple bonds) have shorter lengths, while weaker bonds (like single bonds) have longer lengths. - Electronegativity plays a crucial role in determining bond length. Higher electronegativity leads to stronger attraction between atoms, resulting in shorter bond lengths. ...
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VK JAISWAL ENGLISH-CHEMICAL BONDING (ADVANCED)-SUBJECTIVE PROBLEMS
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  2. There are two groups of compounds A and B. Groups A contains three com...

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  5. Consider the following elements A, B, C and D and their outer electron...

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  6. Consider following four compounds: (i) C(x) O(y) (ii) C(x)O(y+1) ...

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  7. Calculate expression (x+y+z) for diatomic molecules. where x=Total n...

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  8. If Hund rule violate, then find the total number of species among foll...

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  9. Consider the following table Than calculate value of experssion...

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  10. Total number of species among following, in which bond angle is equal...

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  11. Total number of unpaired electrons(s) present in both cationic and an...

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  12. Total number of species which has/ have symmetrical electronic distrib...

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  13. Total number of molecules, in which each covalent bond is comprised of...

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  14. Total number of angle in SeCl(4) which are less than 90^(@).

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  15. Consider the following species O(Me)(2), N(SiH(3))(3), CO, O(SiH(3))(2...

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  17. Consider two covalent compounds AL(n(1)) and BL(n(2)), if central atom...

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  18. Calculate the I-I distance in (Å) for given compound H(2)C(2) I(2) if ...

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  19. There are some arrangements of atomic orbitals which are given below: ...

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  20. Number of hybrid orbital C atoms which have 33% p-character in C(CN)(4...

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  21. Max. no. of equal P-O bonds in P(2)O(7)^(4-) ion is :

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